T(x)=-1/10(x-12)^2+10

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Solution for T(x)=-1/10(x-12)^2+10 equation: 



(T)=-1/10(T-12)^2+10

We move all terms to the left:

(T)-(-1/10(T-12)^2+10)=0



Domain of the equation: 10(T-12)^2+10)!=0

T∈R



We multiply all the terms by the denominator


T*10(T-12)^2-1+10)-(=0

We add all the numbers together, and all the variables

T*10(T-12)^2=0

Wy multiply elements

10T^2(T=0

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